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Fixed testing templates from one curvature tag

This chapter studies Lemma 6.6 in Section 6.4 of H, pages 46–47. The source is the fixed October 5, 2026 version of An L3L^3 bound for the trilinear Hilbert transform.

The aim is to turn a four-linear correlation into a large moment of the target residual against a template with the same tag. The nonlinear amplitudes come from one fixed finite family, while linear modulations may still be arbitrary real numbers. The same complexity bound applies whether the source is an original column or a template inserted later. Repeated insertions therefore do not cause the nonlinear complexity to grow.

Finite termination of the catalog under changing projection histories requires the separate argument of Lemma 6.7. This chapter establishes only the same-tag test used there.

Back to the guide to H

1. Fix the tag, the source column, and the required moment

Fix the normalized curvature tag of an original vertex,

(θ,C,λ),θ∈Rd,C∈Qd×d,λ∈R, (\theta,C,\lambda),\quad \theta\in\mathbb R^d,\quad C\in\mathbb Q^{d\times d},\quad\lambda\in\mathbb R,

and put c=(−1,3,−3,1)c=(-1,3,-3,1) and e(t)=exp⁡(2πit)e(t)=\exp(2\pi\mathrm{i}t). Let the basic complexity be H≥e2H\ge\mathrm e^2, with

d≤log⁡H,ht⁡(C)≤H. d\le\log H,\quad \operatorname{ht}(C)\le H.

The original amplitude χ\chi is supported in [−H,H]d[-H,H]^d. The fixed Gevrey constant c0c_0 in Definition 4.1 of the source gives

∥∂αχ∥∞≤Hc0(∣α∣+1)(∣α∣+1)c0(∣α∣+1).(Original amplitude bound) \|\partial^\alpha\chi\|_\infty \le H^{c_0(|\alpha|+1)}(|\alpha|+1)^{c_0(|\alpha|+1)}. \tag{Original amplitude bound}

There is no restriction on the sizes of θ,λ\theta,\lambda or the external linear modulation.

The source slot is ii, the target slot is j≠ij\ne i, and the remaining two slots are a,ba,b. The original source column has the form

ϕi(y)=e(γy)∑n∈Zdχ(θy−n)e ⁣(ci[λy2+(θy)TC(θy−n)]).(Source column) \phi_i(y)=e(\gamma y)\sum_{n\in\mathbb Z^d} \chi(\theta y-n)e\!\left(c_i[\lambda y^2+(\theta y)^TC(\theta y-n)]\right). \tag{Source column}

It is normalized as a bounded physical column, as in the source. Write F∈L2(I)F\in L^2(I) for the target physical residual. The two observer inputs A,B∈L2(I)A,B\in L^2(I) satisfy the normalized norm bounds

∥A∥2,I,∥B∥2,I≤1. \|A\|_{2,I},\|B\|_{2,I}\le1.

The local form HIH_I is the same as in the preceding chapters. Its kernel is smooth and supported where all four coordinates lie in the interior of II. Below, HI(ϕi,F,A,B)H_I(\phi_i,F,A,B) means that the four functions occupy the specified slots i,j,a,bi,j,a,b; their progression coordinates retain the original slot numbering. The proof uses only these smoothness and support conditions, not the four vanishing marginals of the kernel.

We will construct templates Φj,r,β\Phi_{j,r,\beta} with the same tag. If the four-linear form norm for this source and FF is t0>0t_0>0, then some template will satisfy

∣1∣I∣∫IF(y)Φj,r,β(y)‾ dy∣≥t0/H0,H0≤exp⁡ ⁣(C(1+log⁡H)C).(Testing conclusion) \left|\frac1{|I|}\int_I F(y)\overline{\Phi_{j,r,\beta}(y)}\,\mathrm{d}y\right| \ge t_0/H_0,\quad H_0\le\exp\!\left(C(1+\log H)^C\right). \tag{Testing conclusion}

The constants may depend on the fixed kernel and Gevrey parameters. They do not depend on the interval, the insertion rank, or any real modulation.

2. Fix a smooth partition once

Choose a nonnegative smooth function ρ1\rho_1 supported in (−1,1)(-1,1) such that

∑n∈Zρ1(u−n)=1. \sum_{n\in\mathbb Z}\rho_1(u-n)=1.

For example, take a nonnegative bump γ0\gamma_0 in the fixed Gevrey class of the source, strictly positive on [−1/2,1/2][-1/2,1/2], and define

q(u)=∑n∈Zγ0(u−n),ρ1(u)=γ0(u)/q(u). q(u)=\sum_{n\in\mathbb Z}\gamma_0(u-n),\quad \rho_1(u)=\gamma_0(u)/q(u).

The function qq is positive and periodic, with a fixed positive lower bound. Only a fixed number of summands contribute at each point. The Leibniz recursions for products and reciprocals keep ρ1\rho_1 in the same fixed Gevrey order, with fixed constants.

Take the product

ρ(u1,…,ud)=∏ν=1dρ1(uν). \rho(u_1,\ldots,u_d)=\prod_{\nu=1}^d\rho_1(u_\nu).

Then ρ≥0\rho\ge0, its support is contained in (−1,1)d(-1,1)^d, and

∑n∈Zdρ(u−n)=1.(Integer partition) \sum_{n\in\mathbb Z^d}\rho(u-n)=1. \tag{Integer partition}

If the one-dimensional derivatives satisfy ∥ρ1(m)∥∞≤Cm+1(m+1)s(m+1)\|\rho_1^{(m)}\|_\infty\le C^{m+1}(m+1)^{s(m+1)}, the product rule and ∏ναν!≤∣α∣!\prod_\nu\alpha_\nu!\le|\alpha|! imply a bound of the same type in higher dimensions:

∥∂αρ∥∞≤Cd+∣α∣(∣α∣+1)C(∣α∣+1). \|\partial^\alpha\rho\|_\infty \le C^{d+|\alpha|}(|\alpha|+1)^{C(|\alpha|+1)}.

Thus increasing the dimension incurs only an allowed quasipolynomial cost.

3. A finite amplitude family with arbitrary linear modulations

Put R0=H+1R_0=H+1, and choose the integer and residue set

P0=⌈32R0⌉,R={0,…,P0−1}d. P_0=\lceil32R_0\rceil,\quad \mathcal R=\{0,\ldots,P_0-1\}^d.

For each slot ll, residue r∈Rr\in\mathcal R, and real number β\beta, define

Φl,r,β(y)=e(βy)∑n∈Zdρ(θy−n)e ⁣(r⋅(θy−n)P0)e ⁣(cl[λy2+(θy)TC(θy−n)]).(Template) \Phi_{l,r,\beta}(y)=e(\beta y) \sum_{n\in\mathbb Z^d}\rho(\theta y-n) e\!\left(\frac{r\cdot(\theta y-n)}{P_0}\right) e\!\left(c_l[\lambda y^2+(\theta y)^TC(\theta y-n)]\right). \tag{Template}

Every factor other than the nonnegative weight has modulus 11. The integer partition therefore gives

∣Φl,r,β(y)∣≤∑nρ(θy−n)=1.(Template bound) |\Phi_{l,r,\beta}(y)|\le\sum_n\rho(\theta y-n)=1. \tag{Template bound}

There are only P0dP_0^d nonlinear amplitudes, and the logarithm of this number is O(dlog⁡(H+1))O(d\log(H+1)). Since each coordinate satisfies 0≤rν/P0<10\le r_\nu/P_0<1, all amplitude derivatives have bounds uniform in r,βr,\beta.

The external linear modulation β\beta still ranges over all real numbers. Thus the whole template family is not a finite catalog of columns. Only the nonlinear shapes form a finite family; Lemma 6.7 will determine which columns are actually inserted.

We also allow the source amplitude itself to be

χsrc(u)=ρ(u)e(r0⋅u/P0),r0∈R. \chi_{\mathrm{src}}(u)=\rho(u)e(r_0\cdot u/P_0),\quad r_0\in\mathcal R.

Its support and derivative bounds are controlled uniformly by the same basic complexity. Below, χsrc\chi_{\mathrm{src}} always denotes either the original χ\chi or an amplitude of this template form. Neither the period nor the amplitude family is enlarged after an insertion.

4. Four lifts and finitely many integer carries

Along the progression yl=x+lty_l=x+lt, expand the source column over its integer lifts and insert the integer partition in the other three slots. For each slot, write

ul=θyl,dl=ul−nl,nl∈Zd. u_l=\theta y_l,\quad d_l=u_l-n_l,\quad n_l\in\mathbb Z^d.

Here dld_l is a vector lift; dd still denotes the horizontal dimension. Every nonzero term satisfies ∥dl∥∞≤R0\|d_l\|_\infty\le R_0.

Since ul=(1−l)u0+lu1u_l=(1-l)u_0+lu_1,

dl=(1−l)d0+ld1+kl,kl=(1−l)n0+ln1−nl∈Zd.(Carry relation) d_l=(1-l)d_0+ld_1+k_l,\quad k_l=(1-l)n_0+ln_1-n_l\in\mathbb Z^d. \tag{Carry relation}

Here k0=k1=0k_0=k_1=0, so only k2,k3k_2,k_3 need to be enumerated. Moreover,

∥k2∥∞≤4R0,∥k3∥∞≤6R0. \|k_2\|_\infty\le4R_0,\quad \|k_3\|_\infty\le6R_0.

There are therefore at most (12R0+1)2d(12R_0+1)^{2d} possible carry pairs.

Define the matching phase in each slot by

Ψl(yl,nl)=e ⁣(cl[λyl2+ulTCdl]). \Psi_l(y_l,n_l)= e\!\left(c_l[\lambda y_l^2+u_l^TCd_l]\right).

In each of the other three slots, insert both Ψl\Psi_l and its complex conjugate. The product of all four phases can be computed exactly. Using

∑lcl=∑llcl=∑ll2cl=0 \sum_lc_l=\sum_llc_l=\sum_ll^2c_l=0

and the carry relation, we obtain

∑lclλyl2=0,∑lclulTC[(1−l)d0+ld1]=0. \sum_lc_l\lambda y_l^2=0,\quad \sum_lc_lu_l^TC[(1-l)d_0+ld_1]=0.

Hence

∏l=03Ψl(yl,nl)=e ⁣(∑lclulTCkl)=∏le(clθTCkl yl).(Common phase cancellation) \prod_{l=0}^3\Psi_l(y_l,n_l) =e\!\left(\sum_lc_lu_l^TCk_l\right) =\prod_l e(c_l\theta^TCk_l\,y_l). \tag{Common phase cancellation}

Every remaining factor is a linear modulation in its own slot. This is exact, even when θ\theta or λ\lambda is large.

5. Select integer carries exactly with smooth functions

Take a fixed Gevrey function η1\eta_1 with η1(0)=1\eta_1(0)=1, supported in (−1/3,1/3)(-1/3,1/3), and put η(u)=∏ν=1dη1(uν)\eta(u)=\prod_{\nu=1}^d\eta_1(u_\nu). Then

η(k)=1{0}(k),k∈Zd. \eta(k)=\mathbf1_{\{0\}}(k),\quad k\in\mathbb Z^d.

For a possible carry pair κ=(κ2,κ3)\kappa=(\kappa_2,\kappa_3), use the convention κ0=κ1=0\kappa_0=\kappa_1=0 and the product

η(d2+d0−2d1−κ2) η(d3+2d0−3d1−κ3).(Carry selection) \eta(d_2+d_0-2d_1-\kappa_2)\, \eta(d_3+2d_0-3d_1-\kappa_3). \tag{Carry selection}

At the actual lifts, both arguments are integer vectors. This product is therefore exactly the indicator of the specified carry pair. Summing over all allowed κ\kappa gives exactly 11. This is an identity at integer points, not an approximation to a discontinuous constraint.

To take a periodic Fourier expansion, multiply by a fixed smooth cutoff in each dld_l, which on [−R0,R0]d[-R_0,R_0]^d equals 11 and is supported in (−2R0,2R0)d(-2R_0,2R_0)^d. Denote the product of the four cutoffs and the expression above by Fκ(d0,d1,d2,d3)F_\kappa(d_0,d_1,d_2,d_3). Its support lies inside the fundamental box of period P0P_0, so it can be periodized smoothly without changing its values at any actual lift.

We obtain an absolutely convergent expansion

Fκ(d0,d1,d2,d3)=∑ℓ0,…,ℓ3∈Zdaκ,ℓ∏l=03e(ℓl⋅dl/P0).(Separated expansion) F_\kappa(d_0,d_1,d_2,d_3) =\sum_{\ell_0,\ldots,\ell_3\in\mathbb Z^d} a_{\kappa,\ell}\prod_{l=0}^3e(\ell_l\cdot d_l/P_0). \tag{Separated expansion}

The next section bounds the sum of the absolute values of the coefficients. Only after that estimate will we interchange these sums and integrals.

6. Why the absolute Fourier cost is quasipolynomial

We first establish an estimate that can be applied repeatedly. Let FF be a smooth function in nn dimensions, with period P≥1P\ge1 in each coordinate, and write

B2n(F)=max⁡∣α∣≤2n∥∂αF∥∞. B_{2n}(F)=\max_{|\alpha|\le2n}\|\partial^\alpha F\|_\infty.

Rescale to the unit torus, apply (1−Δ)n(1-\Delta)^n, and integrate term by term. This yields

∣F^(k)∣≤(1+4π2∣k∣22)−n(1+n)n(1+P)2nB2n(F). |\widehat F(k)| \le (1+4\pi^2|k|_2^2)^{-n} (1+n)^n(1+P)^{2n}B_{2n}(F).

Count lattice points in cubical shells. The shell of radius mm contains at most Cn(n+1)mn−1C^n(n+1)m^{n-1} points, so

∑k∈Zn(1+4π2∣k∣22)−n≤Cn(n+1). \sum_{k\in\mathbb Z^n}(1+4\pi^2|k|_2^2)^{-n} \le C^n(n+1).

Consequently,

∥F∥W:=∑k∣F^(k)∣≤Cn(n+1)n+1(1+P)2nB2n(F).(Wiener bound) \|F\|_{\mathrm W}:=\sum_k|\widehat F(k)| \le C^n(n+1)^{n+1}(1+P)^{2n}B_{2n}(F). \tag{Wiener bound}

In dimension zero there is only a constant term, which is treated separately by taking its absolute value.

Apply this estimate to FκF_\kappa with n=4dn=4d and P=P0P=P_0. Its derivatives come from fixed Gevrey cutoffs, linear combinations with fixed coefficients of absolute value at most 33, and the product rule. Thus its derivatives through order 8d8d satisfy

log⁡(2+B8d(Fκ))≤C(d+1)log⁡(d+2). \log\bigl(2+B_{8d}(F_\kappa)\bigr) \le C(d+1)\log(d+2).

This holds uniformly over all carry translations κ\kappa. Including the costs of the period P0P_0 and the number of carries, we obtain

∑κ∑ℓ∣aκ,ℓ∣≤exp⁡ ⁣(C(d+1)2(1+log⁡H)).(Total carry cost) \sum_\kappa\sum_\ell|a_{\kappa,\ell}| \le \exp\!\left(C(d+1)^2(1+\log H)\right). \tag{Total carry cost}

This bound leaves room for all the multidimensional differentiations of the required orders. Since d≤log⁡Hd\le\log H, it is quasipolynomial in HH.

7. Reduce to residues before differentiating amplitudes

Fix one separated Fourier term. Each integer vector ℓ\ell has the unique decomposition

ℓ=P0q+r,q∈Zd,r∈R. \ell=P_0q+r,\quad q\in\mathbb Z^d,\quad r\in\mathcal R.

The actual lift is dl=θyl−nld_l=\theta y_l-n_l, so

e(ℓ⋅dl/P0)=e(q⋅θ yl)e(r⋅dl/P0).(Residue reduction) e(\ell\cdot d_l/P_0) =e(q\cdot\theta\,y_l)e(r\cdot d_l/P_0). \tag{Residue reduction}

Here q⋅nlq\cdot n_l is an integer. The possibly large vector qq changes only the external linear modulation; it no longer enters the nonlinear amplitude.

In a nonsource slot l≠il\ne i, phase cancellation leaves

e(clθTCκl yl) zl(yl)∑nlρ(dl)e(ℓl⋅dl/P0)Ψl(yl,nl)‾. e(c_l\theta^TC\kappa_l\,y_l)\, z_l(y_l)\sum_{n_l}\rho(d_l)e(\ell_l\cdot d_l/P_0) \overline{\Psi_l(y_l,n_l)}.

Writing −ℓl=P0ql′+rl′-\ell_l=P_0q_l'+r_l' rewrites this expression exactly as

zl(yl)Φl,rl′,βl(yl)‾,βl=ql′⋅θ−clθTCκl.(Nonsource slots) z_l(y_l)\overline{\Phi_{l,r_l',\beta_l}(y_l)},\quad \beta_l=q_l'\cdot\theta-c_l\theta^TC\kappa_l. \tag{Nonsource slots}

Each βl\beta_l may be any real number, so its size does not need to be estimated.

The source slot still contains a smooth horizontal periodization. Write ℓi=P0qi+ri\ell_i=P_0q_i+r_i and define

hri(u)=∑n∈Zdχsrc(u−n)e(ri⋅(u−n)/P0). h_{r_i}(u)= \sum_{n\in\mathbb Z^d}\chi_{\mathrm{src}}(u-n)e(r_i\cdot(u-n)/P_0).

This is a smooth function on the unit integer torus. At most (2H+3)d(2H+3)^d terms are nonzero at any point, and each coordinate of ri/P0r_i/P_0 is less than 11. The original amplitude bound and the preceding Wiener bound imply

hri(u)=∑m∈Zdbri,me(m⋅u),sup⁡ri∈R∑m∣bri,m∣≤exp⁡ ⁣(C(d+1)2(1+log⁡H)).(Source periodization) h_{r_i}(u)=\sum_{m\in\mathbb Z^d}b_{r_i,m}e(m\cdot u), \quad \sup_{r_i\in\mathcal R}\sum_m|b_{r_i,m}| \le\exp\!\left(C(d+1)^2(1+\log H)\right). \tag{Source periodization}

The original source amplitudes and the template source amplitudes satisfy the same bound. The essential point is to reduce ℓi\ell_i to its residue first. Differentiating an amplitude that still contains an arbitrary ℓi\ell_i would not justify a uniform derivative bound.

Combining the external linear phase, the carry phase, and e((qi+m)⋅θ yi)e((q_i+m)\cdot\theta\,y_i) leaves the source slot with just a linear phase of modulus 11, namely e(γσyi)e(\gamma_\sigma y_i).

8. The exact separated form

Collect all discrete indices into σ\sigma. The preceding calculation expresses the original form exactly as

HI(ϕi,F,A,B)=∑σcσ Bσ,∑σ∣cσ∣≤Hsep, H_I(\phi_i,F,A,B)=\sum_\sigma c_\sigma\,\mathcal B_\sigma, \quad \sum_\sigma|c_\sigma|\le H_{\mathrm{sep}},
Hsep≤exp⁡ ⁣(C(d+1)2(1+log⁡H)),(Absolute separation cost) H_{\mathrm{sep}}\le \exp\!\left(C(d+1)^2(1+\log H)\right), \tag{Absolute separation cost}

The four slots of each Bσ\mathcal B_\sigma contain, respectively,

e(γσyi),F(yj)Φj,σ(yj)‾,A(ya)Φa,σ(ya)‾,B(yb)Φb,σ(yb)‾. e(\gamma_\sigma y_i),\quad F(y_j)\overline{\Phi_{j,\sigma}(y_j)},\quad A(y_a)\overline{\Phi_{a,\sigma}(y_a)},\quad B(y_b)\overline{\Phi_{b,\sigma}(y_b)}.

Every Φl,σ\Phi_{l,\sigma} belongs to the fixed template family of Section 3. Since the templates are bounded by 11, the L2L^2 norms of the two observer inputs do not increase.

These identities can be justified first with finite Fourier sums, then by passing to the limit using absolute coefficient sums, uniform convergence, and continuity of integration. Both the source periodization and the carry expansion converge absolutely, while the original lift sum is finite at every point. Below we separately justify the limit for a target residual with only L2L^2 regularity.

9. Separate the smooth kernel in the two observer coordinates

Fix a term Bσ\mathcal B_\sigma. Write rI=∣I∣r_I=|I| and let xIx_I be the center of the interval. Set

ya=xI+rIu,yb=xI+rIv,u,v∈[−1/2,1/2]. y_a=x_I+r_Iu,\quad y_b=x_I+r_Iv,\quad u,v\in[-1/2,1/2].

The target coordinate satisfies

yj=αya+βyb,α=b−jb−a,β=j−ab−a,α+β=1.(Target coordinate) y_j=\alpha y_a+\beta y_b,\quad \alpha=\frac{b-j}{b-a},\quad \beta=\frac{j-a}{b-a}, \quad \alpha+\beta=1. \tag{Target coordinate}

The four slots are distinct, so α,β≠0\alpha,\beta\ne0. Moreover,

1/3≤∣α∣,∣β∣≤3,∣α∣+∣β∣≤5. 1/3\le|\alpha|,|\beta|\le3,\quad |\alpha|+|\beta|\le5.

The source coordinate is also a fixed linear combination of ya,yby_a,y_b. Its linear phase can therefore be absorbed separately into the two observer inputs without changing their L2L^2 norms.

The Jacobian is rI2/∣b−a∣r_I^2/|b-a|, which cancels the scale factor rI−2r_I^{-2} in the local form. The normalized kernel K(u,v)K(u,v) is smooth and supported inside a fixed square; its derivatives of every order are controlled uniformly by the allowed constants of the original kernel. Expanding it on a box of period 88 gives

K(u,v)=∑p,q∈Zkp,qe(pu/8)e(qv/8),∑p,q∣kp,q∣≤Cker.(Kernel separation) K(u,v)=\sum_{p,q\in\mathbb Z}k_{p,q} e(pu/8)e(qv/8),\quad \sum_{p,q}|k_{p,q}|\le C_{\mathrm{ker}}. \tag{Kernel separation}

This is the same Wiener estimate in two dimensions, with a constant independent of I,θ,λI,\theta,\lambda. Each kernel Fourier factor can also be absorbed into the corresponding observer input.

It therefore suffices to bound

∬[−1/2,1/2]2G(αu+βv) A(u)B(v) du dv,(One separated term) \iint_{[-1/2,1/2]^2} G(\alpha u+\beta v)\,\mathcal A(u)\mathcal B(v)\, \mathrm{d}u\,\mathrm{d}v, \tag{One separated term}

Here ∥A∥2,∥B∥2≤1\|\mathcal A\|_2,\|\mathcal B\|_2\le1, and GG is the normalized version of the target FΦj,σ‾F\overline{\Phi_{j,\sigma}}, first extended by zero outside [−1/2,1/2][-1/2,1/2].

10. Target Fourier coefficients are allowed template moments

Write the supremum of all allowed template moments as

M=sup⁡r∈Rβ0∈R∣1rI∫IF(y)Φj,r,β0(y)‾ dy∣. M=\sup_{\substack{r\in\mathcal R\\\beta_0\in\mathbb R}} \left|\frac1{r_I}\int_I F(y)\overline{\Phi_{j,r,\beta_0}(y)}\,\mathrm{d}y\right|.

The template bound and Cauchy–Schwarz give M≤∥F∥2,I<∞M\le\|F\|_{2,I}<\infty.

Since ∣α∣+∣β∣≤5|\alpha|+|\beta|\le5, the target argument in a separated term lies in [−5/2,5/2][-5/2,5/2]. Regard the zero extension of GG as a function on [−4,4][-4,4] and take its Fourier expansion with period 88:

G(z)=∑m∈ZG^(m)e(mz/8),G^(m)=18∫−44G(z)e(−mz/8) dz. G(z)=\sum_{m\in\mathbb Z}\widehat G(m)e(mz/8), \quad \widehat G(m)=\frac18\int_{-4}^4G(z)e(-mz/8)\,\mathrm{d}z.

The whole range of the target argument lies within one fundamental period, so no nonzero periodic copies enter.

Returning to the original interval,

G^(m)=18rI∫IF(y)Φj,σ(y)‾e ⁣(−m(y−xI)8rI) dy. \widehat G(m)=\frac1{8r_I}\int_I F(y)\overline{\Phi_{j,\sigma}(y)} e\!\left(-\frac{m(y-x_I)}{8r_I}\right)\,\mathrm{d}y.

The extra character merely adds m/(8rI)m/(8r_I) to the template's external linear modulation, together with a constant of modulus 11. Therefore

∣G^(m)∣≤M/8.(Target coefficients) |\widehat G(m)|\le M/8. \tag{Target coefficients}

Allowing every real linear modulation is essential here. When rIr_I is small, the added modulation can be very large, but it introduces no new nonlinear complexity.

11. Two nonzero frequency spacings give two Bessel bounds

First truncate the target Fourier sum. Define

Am=∫−1/21/2A(u)e(mαu/8) du,Bm=∫−1/21/2B(v)e(mβv/8) dv. A_m=\int_{-1/2}^{1/2}\mathcal A(u)e(m\alpha u/8)\,\mathrm{d}u,\quad B_m=\int_{-1/2}^{1/2}\mathcal B(v)e(m\beta v/8)\,\mathrm{d}v.

For the first sequence, take the period pα=8/∣α∣p_\alpha=8/|\alpha|. Since

8/3≤pα≤24, 8/3\le p_\alpha\le24,

the observer support of length 11 can be extended by zero to a periodic interval of length pαp_\alpha. Parseval gives

∑m∈Z∣Am∣2=pα∥A∥22≤24. \sum_{m\in\mathbb Z}|A_m|^2 =p_\alpha\|\mathcal A\|_2^2\le24.

The sign of the frequency only reorders the integer indices. The same argument for the second sequence gives

∑m∈Z∣Bm∣2≤24. \sum_{m\in\mathbb Z}|B_m|^2\le24.

Thus the pairing with every finite target Fourier sum satisfies

∣∑mG^(m)AmBm∣≤M8∑m∣AmBm∣≤M8(∑m∣Am∣2)1/2(∑m∣Bm∣2)1/2≤3M.(Two observer square-sum bounds) \left|\sum_m\widehat G(m)A_mB_m\right| \le\frac M8\sum_m|A_mB_m| \le\frac M8 \left(\sum_m|A_m|^2\right)^{1/2} \left(\sum_m|B_m|^2\right)^{1/2} \le3M. \tag{Two observer square-sum bounds}

No arbitrary L2L^2 observer function has been replaced by a pointwise bounded one, and no absolute sum of the target Fourier coefficients has been taken.

We now justify the limit. The target Fourier truncations GNG_N converge on [−4,4][-4,4] in L2L^2 to GG, and

∫[−1/2,1/2]2∣GN(αu+βv)−G(αu+βv)∣2 du dv≤∣α∣−1∥GN−G∥L2([−4,4])2. \int_{[-1/2,1/2]^2} |G_N(\alpha u+\beta v)-G(\alpha u+\beta v)|^2\,\mathrm{d}u\,\mathrm{d}v \le|\alpha|^{-1}\|G_N-G\|_{L^2([-4,4])}^2.

For each fixed vv, this follows by the change of variable z=αu+βvz=\alpha u+\beta v; the range stays within the fundamental period. On the other hand,

∥A(u)B(v)∥L2(du dv)=∥A∥2∥B∥2≤1. \|\mathcal A(u)\mathcal B(v)\|_{L^2(\mathrm{d}u\,\mathrm{d}v)} =\|\mathcal A\|_2\|\mathcal B\|_2\le1.

The pairing is therefore continuous, and the uniform bound 3M3M for finite sums passes to the original L2L^2 target. Pointwise or absolute Fourier convergence is not needed.

12. Sum the bounds and choose an actual template

The absolute cost of kernel separation and Section 11 imply

∣Bσ∣≤3CkerM. |\mathcal B_\sigma|\le3C_{\mathrm{ker}}M.

Summing as in Section 8 gives

∣HI(ϕi,F,A,B)∣≤CtestM,Ctest=3CkerHsep.(The form is controlled by moments) |H_I(\phi_i,F,A,B)| \le C_{\mathrm{test}}M,\quad C_{\mathrm{test}}=3C_{\mathrm{ker}}H_{\mathrm{sep}}. \tag{The form is controlled by moments}

This holds uniformly over all normalized observer inputs.

If the form norm is t0>0t_0>0, first choose observer inputs whose correlation is greater than t0/2t_0/2. Then M>t0/(2Ctest)M>t_0/(2C_{\mathrm{test}}). Although MM need not be attained by a template, the definition of supremum still supplies an actual template whose moment is greater than M/2M/2. Taking

H0=8Ctest, H_0=8C_{\mathrm{test}},

proves the testing conclusion in Section 1, with

H0≤exp⁡ ⁣(C(1+log⁡H)C). H_0\le\exp\!\left(C(1+\log H)^C\right).

The period, residue family, partition functions, and all nonlinear derivative bounds are fixed from the outset. When a template becomes the next source column, its character is again reduced to a residue first, so the same bounds apply. There is no recursive loss that raises the complexity to a new power at every insertion.

In dimension d=0d=0, all integer lift, carry, and residue indices are empty, and the partition is the constant 11. The templates are ordinary quadratic phases with arbitrary linear modulations. The four-phase cancellation and the argument in the two observer coordinates still apply; only the horizontal Fourier expansions are omitted.

13. What this supplies for catalog closure

Lemma 6.6 now supplies the following conclusion: a failed four-linear smallness test forces the target physical residual to have a quantitatively large moment against a same-tag template of fixed complexity. This template can be assigned a new private coordinate and proposed as the next column to insert.

This does not yet bound the total number of failed tests. Other projections change the residual being tested, so one cannot repeatedly apply orthogonal energy bounds as if the residual were a fixed vector. The proof of Lemma 6.7 in H refers to the binary-prefix argument of Lemma 3.4. The next module will first prove in full and apply the first prefix-row estimate of Lemma 3.3 in Section 3.3 of H, then establish finite closure of the main and helper catalogs in Lemma 6.7 under the stated fixed inputs. Uniformity of the template family is an input to that argument, not a substitute for it.