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Appendix: three-variable chart calculations
This appendix concerns Definition 4.1 and Lemmas 4.2–4.4 on pp. 15–20 of H, and proves only the forms needed for the fixed-triple scale estimate. We denote the number of spatial variables by to distinguish it from the accuracy parameter in the main text.
1. Charts, translations, and quantitative dependence
H source, p. 15 · H source, p. 16 · This chapter: main text, Section 4
Write . Consider
where is symmetric, and are an arbitrary real matrix and vector, and is a rational matrix. Complexity means
The fixed-order Gevrey constant does not change with any real frequency. At each point there are at most nonzero lattice terms, so the absolute value of has a quasipolynomial upper bound in . No control of is needed.
Conjugation, products of a fixed number of factors, and affine substitutions preserve this form. Translation deserves an explicit calculation. Choose an integer such that is an integer matrix; we may take . For a horizontal shift , write
Relabel the lattice points and set . Modulo integers,
The last term is constant. The two middle terms enter the unrestricted ordinary linear phase, and the small-shift term involving is absorbed into the smooth amplitude. The support and derivatives of the amplitude depend only on the bounded , not on the possibly large . Translating the ordinary quadratic phase changes only its linear and constant terms. Thus, after recentering at a fixed path point , the complexity remains uniform, and all new real parameters are fixed along that path.
Below, denote quasipolynomial quantities in and the reciprocal of the current threshold. Only a fixed number of such enlargements are made at each step.
2. A large Fourier value controls every small return
H source, p. 16 · H source, p. 17 · This chapter: main text, Section 6
Let be supported in a fixed box, with absolute value and Lipschitz norm at most . Suppose
The Fourier transform uses the exponential . We may choose a uniform such that
and such that is -Lipschitz.
Write
The last definition applies to any square matrix . For any return
translate the variable and relabel the lattice points by . This yields
whenever the parenthesized quantity on the right is at most .
No error depending on is hidden here. Set . The nonconstant increment of the chart phase is
The first two terms equal
The last term contains only , bounded on the amplitude support, and the small quantity . The discarded is an integer. The ordinary quadratic phase contributes , while the increment of the ordinary linear phase is constant. Errors from translating the amplitude and are controlled by the same right side.
Choose with , and set
Take the integer
where is sufficiently large to include the volume constants of unit balls in dimensions at most three. Then set
If the return satisfies , then for every we may apply the return identity to . Consequently, the absolute values of the Fourier transform satisfy
If , the balls of radius around these points are disjoint. The Lipschitz bound implies on each ball. Plancherel then yields
a contradiction. Thus every sufficiently small return satisfies
The reciprocals of all the chosen small quantities remain quasipolynomial in . We have not assumed that the Fourier supremum is attained.
3. Constructing a rational fast space from small returns
H source, p. 17 · H source, p. 18 · Minkowski: Henk, Theorem 1.3, p. 2 · This chapter: main text, Section 6
For two small returns, direct expansion yields
By the explicit choice of above,
The pairing on the left is an integer, so it is zero.
First suppose . Define the centrally symmetric convex body
It contains the cube and has nonempty interior. Let and be the successive minima of and , respectively, with respect to the integer lattice. The required transference bound is
For the lower bound, two linearly independent families of integer vectors whose dimensions sum to must have a nonzero integer pairing between them. Apply the polar-body inequality.
The upper bound needs only the upper half of Minkowski's second theorem. Its precise statement appears in Martin Henk, Successive Minima and Lattice Points, Theorem 1.3, p. 2:
where is a centrally symmetric convex body with nonempty interior and is a full-rank lattice.
To apply it, choose from the columns of a matrix with largest absolute determinant. Maximality and convexity yield the following inclusions:
Therefore
Multiplying the two Minkowski upper bounds yields
Every reverse-order product is already at least , so each is at most their total product. This proves the transference bound.
Take
Among the half-open intervals
one contains no successive minimum. Denote its left endpoint by . Set
Every generating integer vector can be written as
Then defines a small return within the threshold . The integer pairing above is zero, proving
The threshold also has an explicit lower bound:
Since , this reciprocal is still a quasipolynomial quantity of the required type.
Suppose . The empty interval ensures . The transference bound provides independent integer vectors
Their pairings with the short integer vectors generating have absolute value less than , so the pairings vanish. These vectors therefore span exactly . The definition of the polar body also implies
Let be the full-row-rank integer matrix with these rows, and define
The Gram matrix is an invertible integer matrix with determinant at least . Cramer's rule and the bounded integer minors control both the rational height of and the size of
All bounds are quasipolynomial. If , simply take .
4. Controlling the effective quadratic matrix in each of three coordinate directions
H source, p. 17 · H source, p. 18 · This chapter: main text, Section 6
Write and define
For each coordinate vector , sample at equally spaced points in the values
Partition the horizontal torus into cubes of side length at most . With more sample points than cubes, two points lie in the same cube. Their difference yields
Increase the absolute constant if needed to handle noninteger partition counts. This return still satisfies the threshold . Its integer part satisfies , so .
Thus
and isotropy removes the fast component:
The already controlled quantities bound this expression quasipolynomially.
The matrix identity is
Substituting into the return increment yields
Every term on the right is controlled. Dividing by , which has a quantitative lower bound, controls column by column. There are at most three columns, so
When , there is no horizontal matrix or chart lattice. Every sufficiently small is a return, and . Taking directly controls , without introducing a zero-dimensional convex body.
5. Obtaining frequencies of a fixed form after splitting
H source, p. 18 · H source, p. 19 · H source, p. 20 · This chapter: main text, Section 6
Now assume only that a rational splitting has been obtained, with its height and the sizes of and at most . This section no longer uses a large Fourier value.
Set
The symmetric part satisfies
Isotropy means that the bilinear form defined by vanishes whenever both arguments lie in the fast space, so
The ordinary quadratic part in the first identity and the first term in the second, together with , combine to form .
Choose an even integer clearing the denominators of . Then
depends only on . Let be a common denominator of . On the fixed box, is bounded and lies in the amplitude support, so
lies in a bounded box of . There are only quasipolynomially many possible and residue classes .
Group terms by and . Remove the known residue-class constant and the linear phase
To Fourier expand the remaining amplitude, introduce two independent variables . All cutoffs below come from one fixed Gevrey cutoff by coordinate products, translations, and dilations at controlled scales, so they have uniform corresponding Gevrey derivative bounds. Choose so that on all possible its value is , with support in . We may take , where the fixed constant bounds the Euclidean norm on the box in use. Choose a smooth function such that
Define
At , the input to the equality cutoff is . This is a lattice point with denominator , so the cutoff keeps exactly the specified group, not an approximate group.
In , this function has period . Choose the controlled integer . The support of then lies strictly inside this period box, allowing periodization in the direction. The Fourier modes are
Substitute and restore the linear phase above to obtain
Thus we have the exact, absolutely convergent expansion
This explains the form in the main text. The remaining real horizontal values enter only through ; they do not become unbounded rational coefficients.
6. Truncation, different splittings, and a fixed rational evaluation family
H source, p. 19 · H source, p. 20 · This chapter: main text, Section 5 · This chapter: main text, Section 6 · This chapter: main text, Section 7
All cutoff scales, periods, numbers of lattice groups, amplitude supports, and bounded phase coefficients are controlled by a quasipolynomial quantity in , denoted by . After normalizing each periodic variable to period one, the product and chain rules yield
This bound does not involve the unbounded fast part of . The differentiation variables are ; we have not differentiated the composition with .
For a nonzero Fourier index , choose its coordinate with largest absolute value and integrate by parts times. This yields
A shell contains at most indices. Taking to be a sufficiently large fixed multiple of bounds the absolute coefficient sum over all groups in this shell by
Since , the prefactor for this fixed high derivative order is still quasipolynomial. The total absolute coefficient sum is therefore at most , and the tail above is at most . Given , choose quasipolynomial in . This yields the uniform sup-norm truncation required in the main text.
The entries of the rational projection matrices have height at most . The number of such matrices is at most
We may first take the coefficient bounds above for every possible matrix and bounded group, then sum them. The cost is still quasipolynomial. Not every matrix needs to occur as a Weyl splitting at some scale. The actual splitting may vary within this fixed finite set.
Within the truncation range, all rational entries of have uniformly quasipolynomial height. Matrix multiplication, summation in fixed dimension, and clearing denominators also bound the height of quasipolynomially. For the rescaled family
the unscaled entries of the effective quadratic matrix are rational linear combinations of the entries of and pairwise products of entries of . The linear frequencies are rational linear combinations of the entries of and .
We may therefore collect these finitely many unscaled real quantities into . Its dimension is bounded by a fixed polynomial in the horizontal dimension, and all evaluation coefficients have height at most
This is all the uniformity needed for the fixed-triple scale count. No numerical upper bound on large real frequencies is needed, and the same rational fast space need not work at every scale.
7. Scope of the verification
H source, p. 15 · H source, p. 16 · H source, p. 17 · H source, p. 18 · H source, p. 19 · H source, p. 20 · This chapter: main text, Section 14
The derivation above reconstructs the Weyl output and finite expansion on pp. 16–20 used for the three-variable six-atom integral. The classical inputs are the explicitly stated upper bound in Minkowski's second theorem, together with Plancherel, integration by parts, and smooth periodic Fourier expansion in finite-dimensional Fourier analysis. The absolute convergence and quantitative tail of the last expansion have been developed in this appendix.
This appendix does not reconstruct the inverse theorem or detection lemma in Section 4, or supply the basic-catalog construction in Proposition 5.6. The main text develops the path budget and deletion error from the supplied basic data.
Return to the proof sequence in DH Lemma 9.1: the finite-counting proof